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1.3x^2-1.66=0
a = 1.3; b = 0; c = -1.66;
Δ = b2-4ac
Δ = 02-4·1.3·(-1.66)
Δ = 8.632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8.632}}{2*1.3}=\frac{0-\sqrt{8.632}}{2.6} =-\frac{\sqrt{}}{2.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8.632}}{2*1.3}=\frac{0+\sqrt{8.632}}{2.6} =\frac{\sqrt{}}{2.6} $
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